Question

Question 1 (v)
Solve the following pair of linear equations by the substitution method.
$\sqrt{2}x+\sqrt{3}y=0;\sqrt{3}x-\sqrt{8}y=0$

Answer 1

$\sqrt{2}x+\sqrt{3}y=0\left(1\right)\sqrt{3}x-\sqrt{8}y=0\left(2\right)\text{From equation (1), we obtain}x=\frac{-\sqrt{3}y}{\sqrt{2}}\left(3\right)\text{Substituting this value in equation (2), we obtain}\sqrt{3}(-\frac{\sqrt{3}y}{\sqrt{2}})-\sqrt{8}y=0\frac{-3y}{\sqrt{2}}-2\sqrt{2y}=0y(-\frac{3}{\sqrt{2}}-2\sqrt{2})=0y=0\text{Substituting this value in equation (3), we obtain}x=0\therefore x=0,y=0$