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Question 82 v...

Question

Question 82 (v)

Subtract

2ab + 5bc - 7ac from 5ab - 2bc - 2ac + 10abc

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Solution

We have, 2ab + 5bc - 7ac and 5ab - 2bc - 2ac + 10abc
The required difference is given by (5ab - 2bc - 2ac + 10abc) - (2ab + 5bc - 7ac)
= 5ab - 2bc - 2ac + 10abc - 2ab - 5bc + 7ac
= (5ab - 2ab) + (-2bc - 5bc) + (-2ac + 7ac) + 10abc
[grouping like terms]
= 3ab - 7bc + 5ac + 10abc

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Question 82 (v)

Subtract

2ab + 5bc - 7ac from 5ab - 2bc - 2ac + 10abc

2 a b + 5 b c - 7 a c

5 a b - 2 b c - 2 a c + 10 a b c

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(7 a b + 2 b c + 10 c a)

Q. Subtract the polynomial

2 a b + 5 b c - 3 c a

from the polynomial

7 a b - 2 b c + 10 c a

Q. Question 11

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