Question

v-t graph of a particle moving in a straight line is as shown in figure. The whole graph is made up of four straight lines P, Q, R and S. These four straight line indicate four type of motions $(M_1...M_4)$ discussed above. State, which straight line corresponds to which type of motion.

• A. $P\to M_2;Q\to M_1;R\to M_4;S\to M_3$
• B. $P\to M_4;Q\to M_3;R\to M_2;S\to M_1$
• C. $P\to M_1;Q\to M_2;R\to M_4;S\to M_3$
• D. $P\to M_1;Q\to M_2;R\to M_3;S\to M_4$

Answer 1

The correct option is D $P\to M_1;Q\to M_2;R\to M_3;S\to M_4$

Region P : Velocity is positive and increasing $⟹$ particle is accelerating i.e $a$ is positive

Region Q : Velocity is positive but decreasing $⟹$ particle is retarding i.e $a$ is negative

Region R : Velocity is negative and decreasing $⟹$ particle is retarding i.e $a$ is negative

Region S : Velocity is negative but increasing $⟹$ particle is accelerating i.e $a$ is positive

Hence option D is correct.