Question

Valence shell electronic configuration of $C{r}^{2+}$ is:

• A. $4s^{0}3d^4$
• B. $4s^{2}3d^2$
• C. $4s^{2}3d^0$
• D. $3p^{6}4s^2$

Answer 1

The correct option is A $4s^{0}3d^4$

Explanation :
Cr has the electronic configuration of: $4s^{1}3d^5$ from which we remove two electrons. So the electronic configuration is: $4s^{0}3d^4$

$C{r}^{2+}$ (22 electrons) : $\left[Ar\right]3d^4$