Question

Valency of potassium ($K$) in $K_{4}Fe(CN{)}_6$ is :

• A. 2
• B. 1
• C. 2/3
• D. 4

Answer 1

Answer: (B)

1

$K_4\left[Fe\right(CH{)}_6]\leftrightharpoons 4K^{+}+[Fe(CN{)}_6{]}^{4-}$

Hence, the oxidation number of potassium is $+1$.