Value of $(3 + \sqrt{5}) (3 - \sqrt{5})$ is .

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Solution

The correct option is D 4
We know the identity: $a^{2} - b^{2} = (a + b) (a - b)$

Hence,
$(3 + \sqrt{5}) (3 - \sqrt{5}) = 3^{2} - (\sqrt{5})^{2} = 9 - 5 = 4$

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Similar questions

Find the value of $(3 + \sqrt{5}) (3 - \sqrt{5})$ .

p = \frac{3 - \sqrt{5}}{3 + \sqrt{5}} and q = \frac{3 + \sqrt{5}}{3 - \sqrt{5}}

x

{(\frac{3}{5})}^{3} \times {(\frac{3}{5})}^{- 6} = {(\frac{3}{5})}^{1 - 2 x}

5 \sqrt{5} \times 5^{3} \div 5^{- \frac{3}{2}} = 5^{a + 2}

a

{(3 \sqrt{5})}^{3}

a \sqrt{5}

a

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