The correct option is A 36 Given, 3! × 3! wkt 3! = 1 × 2 × 3=6 Now, 3! × 3! = 6 × 6 =36 ...

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Standard VI

Mathematics

Distributivity

Value of 3!...

Question

Value of $3! \times 3! = . . . .$

36

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Solution

The correct option is A $36$
Given,

$3! \times 3!$

wkt $3! = 1 \times 2 \times 3 = 6$

Now,

$3! \times 3! = 6 \times 6 = 36$

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Similar questions

Q. Factorise:

2 \sqrt{2} a^{3} + 3 \sqrt{3} b^{3} + c^{3} - 3 \sqrt{6} a b c

Q. Find the value of the determinant:

∣ ∣ ∣ \begin{matrix} \sqrt{2} & 2 \sqrt{3} 3 \sqrt{2} & \sqrt{3} \end{matrix} ∣ ∣ ∣

Given a = 6 + √3
⇒ (1/a) = 1 / (6 + √3)
Multiply and divide by (6 − √3)
⇒ (1/a) = (6− √3) / [(6 + √3)(6 − √3)]
⇒ (1/a) = (6 − √3) / [36 − 3]
⇒ (1/a) = (6− √3)/33
∴ a - (1/a) = (6 + √3) -(6 − √3)/33
= [33(6 + √3) - (6 - √3)]/33
= [32*6 + 34*√3]/33
= [192 + 34√3]/33

Answer : [192 + 34√3]/33

Why does 1/a come above

Simplify:

(1)