Value of c in Lagrange's mean value theorem for the function f(x)=x2−3x+5 in the interval [1,4] is:
A
2.5
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B
3.5
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C
3
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D
2
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Solution
The correct option is A2.5 The given quadratic function is continuous and differentiable on the entire set of real numbers. Hence, we can apply Lagrange's mean value theorem. f′(x)=2x−3 f′(c)=f(b)−f(a)b−a, ⇒2c−3=(42−3⋅4+5)−(12−3⋅1+5)4−1 ⇒2c−3=2⇒2c=5⇒c=2.5