Value of cos -1 3 5 -sin -1 4 5 is

The correct option is B 0 cos^ 135 = sin^ 1 ( √(5^2 3^2)5 ) #160; = sin^ 145 ⇒cos^ 135 sin^ 145 = 0 ...

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Value of co...

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Value of ${cos}^{- 1} \frac{3}{5} - {sin}^{- 1} \frac{4}{5}$ is

1

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- 1

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\frac{4}{5}

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{cos}^{- 1} \frac{3}{5} - {sin}^{- 1} \frac{4}{5}

x = 4 {log}_{5} 2 + {log}_{5} sin \frac{π}{5} + {log}_{5} sin \frac{2 π}{5} + {log}_{5} sin \frac{3 π}{5} + {log}_{5} sin \frac{4 π}{5}

1

sin 18^{o} = \frac{1}{4} (\sqrt{5} - 1)

cos 36^{o} = \frac{1}{4} (\sqrt{5} + 1)

∣ ∣ ∣ ∣ ∣ \begin{matrix} {tan}^{- 1} x & {cot}^{- 1} x & π / 2 {sin}^{- 1} (4 / 5) & {sin}^{- 1} (3 / 5) & {sin}^{- 1} 1 {cos}^{- 1} (3 / 5) & {cos}^{- 1} (4 / 5) & 1 \end{matrix} ∣ ∣ ∣ ∣ ∣

x

2 {cos}^{- 1} x = {cos}^{- 1} (2 x^{2} - 1)

- 1 \leq x \leq 1

cos [{sin}^{- 1} (\frac{- 4}{5}) - {cos}^{- 1} (\frac{4}{5})] =

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