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Question

Value of cot[π42cot13]

A
3
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B
7
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C
9
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D
34
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Solution

The correct option is B 7
Given,

cot[π42cot13]

Let, cot13=A

=cot[π42A]

=1tan[π42A]

=1+tan2A1tan2A

Now,

cotA=3

tanA=13

tan2A=2tanA1tan2A

=2×131(13)2

=34

cot[π42cot13]=1+34134=7

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