Value of dissociation constant of acetic acid is 10−6, where as dissociation constant of formic acid is 10−5. Which of the following will be the value of pKa(acetic acid) - pKa(formic acid)
a)10
b)1
c)10−1
d)-1
The dissociation constant is Ka and pKa stands for a negative log of Ka. We will now Calculate the pKa of acetic acid and formic acid.
Acetic acid:
Ka = 10−6
pKa= -log(Ka)= -log(10−6) = 6
Formic acid:
Ka=10−5
pKa=−log(Ka)=−log(10−5) =5
The value of pKa(acetic acid) - pKa(formic acid) = 6 - 5 = 1.
Therefore, the correct answer is an option (B).