N2O4(g)⇌2NO2(g) at 288 K is 47.9. The KC for this reaction at same temperature is ........(Nearest integer)
(R=0.083LbarK−1mol−1)
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JEE MAIN 2021
N2O4(g)⇌2NO2(g)
Δng=2−1=1
Kp=Kc(RT)Δng
Kp=Kc(RT)1
Kc=KpRT=47.90.083×288=2