Value of λ for which the function f(x)=2x3−3(λ+2)x2+12λx has one local maxima and one local minima in R, can not be
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is B2 f′(x)=0 must have two real and unequal roots ⇒f′(x)=6x2−6(2+λ)x+12λ=6(x2−(2+λ)x+2λ) D>0⇒(2+λ)2−8λ>0 ⇒(λ−2)2>0
So λ can not be 2.