Question

Value of $({\sin }^{2}30+4{\cot }^{2}45-{\sec }^{2}60)$ is

• A. $0$
• B. $\frac{1}{4}$
• C. $4$
• D. $1$

Answer 1

The correct option is B $\frac{1}{4}$

Taking

$({\sin }^2{30}^0+4{\cot }^2{45}^0-{\sec }^2{60}^0)$

substituting the value of sin ${30}^0$, cot${45}^0$, $sec{60}^0$

$={\left(\frac{1}{2}\right)}^2+4\times {\left(1\right)}^2-2^2$

$=\frac{1}{4}+4-4$

$=\frac{1}{4}$