Value of $(sin 60^{o} cos 30^{o} - cos 60^{o} sin 30^{o})$ is

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{\sqrt{3}}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{1}{2}$
Given that: $(sin 60^{o} cos 30^{o} - cos 60^{o} sin 30^{o})$

$= (\frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2} - \frac{1}{2} \times \frac{1}{2})$

$= (\frac{3}{4} - \frac{1}{4})$

$= \frac{2}{4} = \frac{1}{2}$

Suggest Corrections

Similar questions

sin 60^{o} cos 30^{o} + cos 60^{o} sin 30^{o}

The value of $[2^{3} - 3^{2} - 1^{3}]^{0}$ is 0.

(- 5) \times (- 4) \times (- 3) \times (- 2) \times (- 1) \times 0 + 0 \times (1) \times (2) \times (3) \times (4) \times (5)

\frac{(0.6)^{0} - (0.1)^{1}}{(3 / 2^{3})^{- 1} (3 / 2)^{3} + (- 1 / 3)^{- 1}}

5^{0} + 2^{2} + 4^{0} + 7^{1} - 3^{1}

Join BYJU'S Learning Program