Question

Value of $(\sin {60}^o\cos {30}^o-\cos {60}^o\sin {30}^o)$ is

• A. $0$
• B. $1$
• C. $\frac{1}{2}$
• D. $\frac{\sqrt{3}}{2}$

Answer 1

The correct option is C $\frac{1}{2}$

Given that: $(\sin {60}^o\cos {30}^o-\cos {60}^o\sin {30}^o)$

$=(\frac{\sqrt{3}}{2}\times \frac{\sqrt{3}}{2}-\frac{1}{2}\times \frac{1}{2})$

$=(\frac{3}{4}-\frac{1}{4})$

$=\frac{2}{4}=\frac{1}{2}$