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Value of limx...

Question

Value of $lim x \to 0 \frac{x log (1 + 7 x)}{1 - cos 3 x} =$

A

\frac{5}{9}

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B

\frac{14}{9}

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C

\frac{14}{5}

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D

\frac{7}{5}

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Solution

The correct option is B $\frac{14}{9}$
$L = lim x \to 0 \frac{(\frac{log (1 + 7 x)}{x})}{(\frac{1 - cos 3 x}{x^{2}})} = \frac{7}{(\frac{3^{2}}{2})} = \frac{14}{9}$

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