Value of ${sin}^{2} A + {cos}^{2} A = ?$

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Solution

$S i n^{2} A + C o s^{2} A = (\frac{p}{h})^{2} + (\frac{b}{h})^{2} = \frac{p^{2} + b^{2}}{h^{2}} = 1$

from Pythagoras theorem
$h^{2} = p^{2} + b^{2} ∴ S i n^{2} A + C o s^{2} A = 1$

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