Value of $s i n 37 ° . c o s 53 °$ is

9/25

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12/25

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16/25

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3/5

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Solution

The correct option is A 9/25
$s i n 37 ° . c o s 53 ° = s i n 37. c o s (90 - 37) = s i n^{2} 37 = 9 / 25$

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Similar questions

\frac{{sin}^{2} 53 + {cos}^{2} 53}{{sec}^{2} 37 - {tan}^{2} 37}

s i n 37 ° . c o s 53 °

37^{0}

\times

53^{0}

\frac{s i n 35^{0}}{c o s 55^{0}} + \frac{t a n 37^{0}}{c o t 53^{0}}

({cos}^{2} 37^{\circ} - {sin}^{2} 53^{\circ}) =

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