Question

Value of spin only magnetic moment for one of the following configuration is 2.84 bm.

Answer 1

Dear student

I think this is a multiple choice question and you are suppose to give the options..

Don't worry about that.

I can suggest you an answer which you can refer.

Spin only magnetic moment = √(n(n+2)) BM.

Where n = number of unpaired electron

Given, √(n(n+2)) = 2.84 BM

n(n + 2) = (2.84)^2

=8.0656

n^2+2n=8.0656

Solving this quadratic equation ,we get

n=2

In an octahedral complex, for a d4 configuration in strong field ligand, number of unpaired electrons = 2

This configuration is an example with spin magnetic moment of 2.84BM.