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Byju's Answer
Standard XII
Mathematics
Principal Solution of Trigonometric Equation
Value of θ ...
Question
Value of
θ
(
0
<
θ
<
360
o
)
which satisfy the equation
cosec
θ
+
2
=
0
is:
A
210
o
,
100
o
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B
240
o
,
300
o
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C
210
o
,
240
o
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D
210
o
,
330
o
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Solution
The correct option is
A
210
o
,
330
o
Given:
cosec
θ
+
2
=
0
⇒
sin
θ
=
−
1
2
⇒
θ
=
(
π
+
π
6
)
,
(
2
π
−
π
6
)
⇒
θ
=
7
π
6
,
11
π
6
⇒
θ
=
210
∘
,
330
∘
Suggest Corrections
0
Similar questions
Q.
Lay down the positions of the points whose polar coordinates are
(
1
,
−
210
o
)
Q.
Find the perimeter of a sector whose radius and central angle are
18
cm and
210
o
respectively.
Q.
Find the resultant magnetic moment when
θ
=
240
o
.
Q.
Assertion :Consider the following statements.
The value of
sin
120
o
can be derived by taking
θ
=
240
o
in the equation
2
sin
θ
2
=
√
1
+
sin
θ
−
√
1
−
sin
θ
. Reason: The angles A, B, C and D of any quadrilateral ABCD satisfy the equation
cos
(
1
2
(
A
+
C
)
)
+
cos
(
1
2
(
B
+
D
)
)
=
0
Then the truth value of p and q are respectively.
Q.
In
△
A
B
C
,the value of
t
a
n
A
+
t
a
n
(
A
+
120
o
)
+
t
a
n
(
A
+
240
o
)
t
a
n
3
A
=
?
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