Question

Value of v for which particle hit vertical walls n times is $(xn+\frac{5}{2})$ m/s and finally hit the point A which is the centre point between the two vertical walls (all collison are elastic) Find x.$(g=10m/s^2)$

Answer 1

time taken to hit ground $=\sqrt{\frac{2\times 20}{10}}=2\sec .$

the motion of the ball can be considered a projectile raving range $10n+5$

$\therefore vt=10n+5$

$\Rightarrow v\left(2\right)=10n+5$

$\Rightarrow v=5n+\frac{5}{2}$

$\therefore x=5$ Answer.