Van de Graaff generator consists of a hollow metal sphere of diameter $2 m$ . If the potential on the surface of the sphere is $6$ million volt, the charge accumulated over the surface of the sphere is :

0.66

milli coulomb

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1

coulomb

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8.854

micro coulomb

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0.33

micro coulomb

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Solution

The correct option is A $0.66$ milli coulomb
Radius of sphere $r = \frac{d}{2} = \frac{2}{2} = 1 m$
Potential on the sphere $V = \frac{k q}{r}$
So, $6 \times 10^{6} = \frac{9 \times 10^{9} \times q}{1}$
$⟹ q = 0.66 \times 10^{- 3} C = 0.66 m C$

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Van de Graaff generator consists of a hollow metal sphere of diameter 2m. If the potential on the surface of the sphere is 6 million volt, the charge accumulated over the surface of the sphere is :

The correct option is A 0.66 milli coulombRadius of sphere r=d2=22=1 mPotential on the sphere V=kqrSo, 6×106=9×109×q1⟹ q=0.66 ×10−3 C=0.66 mC

Van de Graaff generator consists of a hollow metal sphere of diameter $2 m$ . If the potential on the surface of the sphere is $6$ million volt, the charge accumulated over the surface of the sphere is :

The correct option is A $0.66$ milli coulomb
Radius of sphere $r = \frac{d}{2} = \frac{2}{2} = 1 m$
Potential on the sphere $V = \frac{k q}{r}$
So, $6 \times 10^{6} = \frac{9 \times 10^{9} \times q}{1}$
$⟹ q = 0.66 \times 10^{- 3} C = 0.66 m C$