van der Waals' constant 'b' of Ar is 3.22×10−5m3mol−1. Calculate the molecular diameter(in nm) of Ar.
A
0.35
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B
0.43
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C
0.29
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D
0.17
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Solution
The correct option is C 0.29 We know that, excluded volume 'b' is given as : b=4× volume occupied by the molecules in one mole of a gas =4×N0×(43πr3) 3.22×10−5=4×6.02×1023×43×227×r3
or r=(3.22×10−5×3×74×6.02×1023×4×22) =0.1472×10−9m ∴ Diameter =2r=2×0.1472×10−9 =0.2944×10−9m=0.2944nm