Question

Van't Hoff factor for a dilute solution of sodium argento cyanide is :

• A. $2$
• B. $0.25$
• C. $0.50$
• D. $3.0$

Answer 1

Answer: (A)

$2$

The compound is $Na\left[Ag\right(CN{)}_2]$.

The dissociation reaction is,

$Na\left[Ag\right(CN{)}_2]\to N{a}^{+}+[Ag(CN{)}_2{]}^{-}$

1 0 0

$1-\alpha$ $\alpha$ $\alpha$

Van't Hoff factor, $i=1+\alpha$

For very dilute solution,

$\because \alpha =1$

Hence, $i=2$

Therefore, option A is correct.