Question

Van't Hoff factor for $TH(N{O}_3{)}_4$ in an aqueous solution is :

Answer 1

1 molecule of $Th(N{O}_3{)}_4$ on dissociation gives fiv ions.
$Th(N{O}_3{)}_4\rightleftharpoons T{h}^{4+}+4N{O}_3^{-}$
Hence, the van't Hoff factor for $Th(N{O}_3{)}_4$ in an aqueous solution is 5.