Van't Hoff's factor of aq. $K_{2} S O_{4}$ at infinite dilution has value equal to:

1

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2

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3

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Between

2

and

3

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Solution

The correct option is C $3$
$K_{2} S O_{4} ⟶ 2 K^{+} + S O_{4}^{2 -}$
At infinite dilution, each molecule gives $3$ ions, hence, the Van't Hoff's factor, $i = 3$ .

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