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Standard XII

Chemistry

Concentration Terms

Vapor pressur...

Question

Vapor pressure of pure liquid A is 40 m bar. When solution is with liquid A & liquid B, the vapour pressure of A is found to be 32 m bar. What is the mole fraction of A?

0.6

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0.7

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0.8

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0.2

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Solution

The correct option is C 0.8
Vapour pressure of A in solution is given $(P_{A})$ & Vapour pressure of pure A is given $(P_{A}^{\circ})$
$P_{A} = P_{A}^{\circ} . X_{A} \to$ according to Raoult's law
$32 = 40 \times X_{A}$
$X_{A} = \frac{32}{40} = 0.8$

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Vapor pressure of pure liquid A is 40 m bar. When solution is with liquid A & liquid B, the vapour pressure of A is found to be 32 m bar. What is the mole fraction of A?

The correct option is C 0.8Vapour pressure of A in solution is given (PA) & Vapour pressure of pure A is given (P∘A) PA=P∘A.XA→ according to Raoult's law 32=40×XA XA=3240=0.8

The correct option is C 0.8
Vapour pressure of A in solution is given $(P_{A})$ & Vapour pressure of pure A is given $(P_{A}^{\circ})$
$P_{A} = P_{A}^{\circ} . X_{A} \to$ according to Raoult's law
$32 = 40 \times X_{A}$
$X_{A} = \frac{32}{40} = 0.8$