Question

Vapour density of a gas is 11.2 . The volume occupied by 11.2 g of this gas at STP is:

• A. $22.4l$
• B. $11.2l$
• C. $1l$
• D. $2.25l$

Answer 1

The correct option is B $11.2l$

$Vapourdensity=\frac{molecularweight}{2}$
$\therefore$ Molecular weight is $22.4g/mole$.
At STP, volume occupied by 1 mole of gas is $22.4l$ and therefore, volume occupied by 0.5 moles (11.2 g) of gas will be $11.2l$.