Vapour density of methane is___________-

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Solution

Part: 1: Introduction of Vapor density
At the same temperature and pressure conditions, the relative density of a gas or vapor to that of Hydrogen $(H_{2})$ is called vapor density.
Vapor density is the ratio of the molar mass of gas and the molar mass of Hydrogen $(H_{2})$ .
The molar mass of Hydrogen $(H_{2})$ is equal to $2 \frac{g}{m o l}$
So,
$V a p o r d e n s i t y = \frac{m o l a r m a s s o f g a s}{m o l a r m a s s o f H y d r o g e n (H_{2})} V a p o r d e n s i t y = \frac{m o l a r m a s s o f g a s}{2 \frac{g}{m o l}}$

Part:2: Calculation of Methane $(C H_{4})$ vapor density:
The molar mass of the methane $(C H_{4})$ is $16 \frac{g}{m o l}$
The vapor density will be
$V a p o r d e n s i t y = \frac{m o l a r m a s s o f M e t h a n e (C H_{4})}{2 \frac{g}{m o l}} V a p o r d e n s i t y = \frac{16 \frac{g}{m o l}}{2 \frac{g}{m o l}} V a p o r d e n s i t y = 8$
Therefore, methane $(C H_{4})$ vapor density is 8.

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