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Standard XII

Chemistry

Liquids in Liquids

Vapour pressu...

Question

Vapour pressure of $C C l_{4}$ at $25^{O} C$ is 143mm Hg. 0.5gm of a non-volatile solute (mol. wt. 65) is dissolved in 100ml of $C C l_{4}$ . Find the vapour pressure of the solution.
(Density of $C C l_{4} = 1.58 g m / {c m}^{3}$ )

141.93 mm

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94.39 mm

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199.34 mm

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143.99 mm

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Solution

The correct option is A 141.93 mm
Here logically the option A is correct because when the non-volatile solute is added is added to the solvent the vapour pressure of the solution gets lowered and here only option A has a vapour pressure less than the vapour pressure of the solvent.

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Similar questions

Vapour pressure of CCl₄ at 25⁰C is 143mm of Hg. 0.5 gm of a non-volatile solute (mol. wt. = 65) is dissolved in 100ml CCl₄. Find the vapour pressure of the solution (Density of CCl₄=1.58g/cm²)

Q. Vapour pressure of

C C l_{4}

25^{o} C

143 m m H g

. If

0.5 g m

of non-volatile solute (mol. mass 65) is dissolved in

100 m l C C l_{4}

, then the vapour pressure of the solution at

25^{o} C

is:

[Given: density of

C C l_{4} = 1.58 g / c m^{3}

]

Q. Vapour pressure of

C C l_{4}

25^{o}

C is

143

mm of Hg.

0.5

g of a non-volatile solute (mol. Mass

= 65

) is dissolved in

100

C C l_{4}

. Find the vapour pressure of the solution: (Density of

C C l_{4} = 1.58 g / c m^{3}

)

Q. 0.5 g of a nonvolatile organic compound (molecular weight 65) is dissolved in

100 m L o f C C l_{4}

. If the vapour pressure of pure

C C l_{4} i s 140 m m H g

, then calculate the vapour pressure of the solution.

(Density of C C l_{4} solution is 1.6 g m L^{- 1}

Q. Vapour pressure of pure benzene is

640 m m

and its mol. wt. is

78

. When

2.175 g

of a non-volatile substance is dissolved in

39 g

benzene the vapour pressure of the solution becomes

600 m m

. Calculate mol. wt. of solute.

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Vapour pressure of CCl4 at 25OC is 143mm Hg. 0.5gm of a non-volatile solute (mol. wt. 65) is dissolved in 100ml of CCl4. Find the vapour pressure of the solution.(Density of CCl4=1.58gm/cm3)

The correct option is A 141.93 mmHere logically the option A is correct because when the non-volatile solute is added is added to the solvent the vapour pressure of the solution gets lowered and here only option A has a vapour pressure less than the vapour pressure of the solvent.

Vapour pressure of $C C l_{4}$ at $25^{O} C$ is 143mm Hg. 0.5gm of a non-volatile solute (mol. wt. 65) is dissolved in 100ml of $C C l_{4}$ . Find the vapour pressure of the solution.
(Density of $C C l_{4} = 1.58 g m / {c m}^{3}$ )

The correct option is A 141.93 mm
Here logically the option A is correct because when the non-volatile solute is added is added to the solvent the vapour pressure of the solution gets lowered and here only option A has a vapour pressure less than the vapour pressure of the solvent.