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Median from Frequency Distribution Table

Variable 4 ...

Question

Variable $4$ $8$ $9$ $10$ $11$ $12$ $13$
Frequency $3$ $4$ $5$ $8$ $4$ $3$ $2$
Mode of the distribution

8

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9

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10

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None of these

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Solution

The correct option is C $10$
We know mode of a distribution is the term corresponding to maximum frequency.
Thus in the given distribution $8$ is the maximum frequency and corresponding mode is $10$ .

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Similar questions

$x$	$10$	$11$	$12$	$13$	$14$	$15$
$f$	$1$	$4$	$7$	$5$	$9$	$8$

$χ$	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$	$9$	$10$
$f$	$4$	$6$	$8$	$12$	$17$	$11$	$7$	$6$	$5$	$3$

If the mean of the following frequency distribution is 4.5, find the misssing frequency f.

$\begin{matrix} Variable & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 Frequency & 5 & 12 & f & 13 & 7 & 9 & 12 & 3 & 11 & 4 \end{matrix}$

\frac{11}{12} \div (\frac{5}{9} \times \frac{18}{25})

(2 \frac{1}{2} \times \frac{8}{10}) \div (1 \frac{1}{2} + \frac{5}{8})

\frac{15}{16}

(\frac{5}{6} - \frac{1}{2}) \div \frac{10}{11}

\frac{9}{8} \div \frac{3}{5}

(\frac{3}{4} + \frac{3}{5})

\frac{2}{5} \div {\frac{1}{5} o f [\frac{3}{4} - \frac{1}{2}] - 1}

(1 \frac{3}{4} \times 3 \frac{1}{7}) - (4 \frac{3}{8} \div 5 \frac{3}{5})

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Variable	$4$	$8$	$9$	$10$	$11$	$12$	$13$
Frequency	$3$	$4$	$5$	$8$	$4$	$3$	$2$