Variate X 1 2 3 4 5
Frequency of X 4 5 k 1 2
If the mean of variate $X$ in the distribution is $2.6$ , then find the value of $k$

Open in App

Solution

xi ti fixi
1 4 4
2 5 10
3 k 3k
4 1 4
5 2 10
$\sum f i = 12 + k$ $\sum f i x i = 28 + 3 k$
$¯ x = \frac{\sum f i x i}{\sum f i} = 2.6$

$\frac{28 + 3 k}{12 + k} = 2.6$

$28 + 3 k = 31.2 + 2.6 k$

$0.4 k = 3.2$

$k = 8$

Suggest Corrections

Similar questions

Variate X	1	2	3	4	5
Frequency of X	4	5	k	1	2

\begin{matrix} V a r i a t e & 6 & 7 & 1.9 & 9 & 10 F r e q u e n c y & 1 & 2 & k & 3 & 4 \end{matrix}

3.6

k

X	$2$	$3$	$4$	$5$	$6$
frequency	$2$	$7$	$14$	$22$	$30$

X = 5

2.6

$x_{i}$	$1$	$2$	$3$	$4$	$5$
$f_{i}$	$5$	$4$	$f$	$2$	$3$

p

18

Variate $(x)$	$13$	$15$	$17$	$19$	$20 + p$	$23$
Frequency $(f)$	$8$	$2$	$3$	$4$	$5 p$	$6$

Join BYJU'S Learning Program