Variation of electric field along x-axis is shown in figure. If potential at origin is 10 V, then potential at x = 2 is
A
50 V
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B
-10 V
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C
30 V
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D
-40 V
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Solution
The correct option is D -40 V Change in potential difference is negative of area under E - x graph. Area under the graph, 12×2×50=50 ⇒ΔV=−50V So, potential at x =2 is (10−50)=−40V