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Standard XII

Physics

Electric Field Due to a Sphere and Thin Shell

Variation of ...

Question

Variation of electric field along x-axis is shown in figure. If potential at origin is 10 V, then potential at x = 2 is

50 V

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-10 V

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30 V

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-40 V

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Solution

The correct option is D -40 V
Change in potential difference is negative of area under E - x graph.
Area under the graph,
$\frac{1}{2} \times 2 \times 50 = 50$
$\Rightarrow Δ V = - 50 V$
So, potential at x =2 is $(10 - 50) = - 40 V$

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Variation of electric field along x-axis is shown in figure. If potential at origin is 10 V, then potential at x = 2 is

The correct option is D -40 VChange in potential difference is negative of area under E - x graph. Area under the graph, 12×2×50=50 ⇒ΔV=−50 V So, potential at x =2 is (10−50)=−40 V

The correct option is D -40 V
Change in potential difference is negative of area under E - x graph.
Area under the graph,
$\frac{1}{2} \times 2 \times 50 = 50$
$\Rightarrow Δ V = - 50 V$
So, potential at x =2 is $(10 - 50) = - 40 V$