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Question

Variation of equilibrium constant K with temperature T is given by van't Hoff equation:
logK=logAΔHo2.303RT
A graph between logK and T1 was a straight line as shown in the figure and having θ=tan1(0.5) and OP=10. Calculate:
(a) ΔHo (Standard heat of reaction) when T=298K
(b) A (pre-exponential factor)
(c) Equilibrium constant K at 298K
(d) K at 798K, if ΔHo is independent of temperature
657997_2c70abb70e474ff9a5291a27f83787ea.png

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Solution

Explanation:

a) log10K=log10AΔHo2.303RT

It is an equation of a straight line of the y=c+mx

Slope m tanθ= ΔHo2.303R

0.5=ΔH02.303×8.314

ΔHo=9.574Jmol1


b) Intercept,D=log10A=10A=1010

D=1010


c) logK=109.5742.303×8.314×298

K=9.96×109


d) logK2K1=ΔH20303×R(1T11T2)

log(K2)9.96×109=1.05×103

log(K2)=9.98×106

K2=e9.98×106

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