Question

Variation of force with time is given as in figure. If initial momentum of a of body is $10kgm{s}^{-1}$ then, its final momentum after $4s$, will be

Answer 1

We know that area under Force-time graph gives us change in momentum

$\Rightarrow A=\Delta p$

$\Delta p=\frac{1}{2}\times 4\times 4$

$=8kgm/s$

So,its final momentum after 4 s = Initial Momentum + Change in Momentum

$\Rightarrow$ Final Momentum $=10+8=18kgm/s$