Variation of velocity with time of particle is straight line as shown below. Find the slope of this straight line

0.66

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1.33

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2.33

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0.33

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Solution

The correct option is B 1.33
$t_{1} = 2 s, t_{2} = 5 s v_{1} = 3 m / s, v_{2} = 7 m / s$
$s l o p e = \frac{(v_{2} - v_{1})}{(t_{2} - t_{1})} = \frac{(7 - 3)}{(5 - 2)} = \frac{4}{3} = 1.33$

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Variation of velocity with time of particle is straight line as shown below. Find the slope of this straight line

The correct option is B 1.33t1=2s,t2=5sv1=3m/s,v2=7m/s slope=(v2−v1)(t2−t1)=(7−3)(5−2)=43=1.33

The correct option is B 1.33
$t_{1} = 2 s, t_{2} = 5 s v_{1} = 3 m / s, v_{2} = 7 m / s$
$s l o p e = \frac{(v_{2} - v_{1})}{(t_{2} - t_{1})} = \frac{(7 - 3)}{(5 - 2)} = \frac{4}{3} = 1.33$