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Question

# Various modes of transport used by 1260 students in a given school are given below: School bus Private bus Bicycle Rickshaw On foot 350 245 210 175 280 Represent the above data by a pie chart.

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Solution

## $\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{students}=1260\phantom{\rule{0ex}{0ex}}\mathrm{Central}\mathrm{angle}\mathrm{of}\mathrm{each}\mathrm{component}=\left(\frac{\mathrm{number}\mathrm{of}\mathrm{students}\mathrm{using}\mathrm{that}\mathrm{mode}}{\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{students}}×360\right)°\phantom{\rule{0ex}{0ex}}\mathbf{Calculation}\mathbf{}\mathbf{of}\mathbf{}\mathbf{central}\mathbf{}\mathbf{angles}$ Mode of transport Number of students Central angle School bus 350 $100°$ Private bus 245 $70°$ Bicycle 210 $60°$ Rickshaw 175 $50°$ On foot 280 $80°$ $\mathbf{Construction}\mathbf{}\mathbf{of}\mathbf{}\mathbf{pie}\mathbf{}\mathbf{chart}\phantom{\rule{0ex}{0ex}}\mathrm{Steps}\mathrm{of}\mathrm{construction}:\phantom{\rule{0ex}{0ex}}1.\mathrm{Draw}\mathrm{a}\mathrm{circle}\mathrm{of}\mathrm{any}\mathrm{convenient}\mathrm{radius}.\phantom{\rule{0ex}{0ex}}2.\mathrm{Draw}\mathrm{a}\mathrm{horizontal}\mathrm{radius}\mathrm{of}\mathrm{this}\mathrm{circle}.\phantom{\rule{0ex}{0ex}}3.\mathrm{Draw}\mathrm{sectors}\mathrm{whose}\mathrm{central}\mathrm{angles}\mathrm{are}100°,70°,60°,50°\mathrm{and}80°.\phantom{\rule{0ex}{0ex}}4.\mathrm{Shade}\mathrm{the}\mathrm{sectors}\mathrm{so}\mathrm{obtained}\mathrm{differently}\mathrm{and}\mathrm{label}\mathrm{each}\mathrm{one}\mathrm{of}\mathrm{them}.\phantom{\rule{0ex}{0ex}}\mathrm{Thus},\mathrm{we}\mathrm{obtain}\mathrm{the}\mathrm{required}\mathrm{pie}\mathrm{chart}\mathrm{as}\mathrm{shown}\mathrm{in}\mathrm{the}\mathrm{figure}\mathrm{below}.$

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