Varun purchased two TV sets for rupees 30000.he sold at a loss of 15% and other at a gain of 19%.the selling price in both the cases was the same.find the cost price of each TV set.

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Solution

Answer :
Given : Varun purchased two TV sets for rupees 30000.
Let cost price of first T.V = x
Then
Cost price of second T.V. = 30000 - x
And
Also given : He sold at a loss of 15% and other at a gain of 19%.the selling price in both the cases was the same.
So, we get

x - 15% of x = ( 30000 - x ) + 19% of ( 30000 - x )

$\Rightarrow x - \frac{15 x}{100} = (30000 - x) + \frac{19 (30000 - x)}{100} \Rightarrow x - \frac{3 x}{20} = \frac{100 (30000 - x) + 19 (30000 - x)}{100} \Rightarrow \frac{20 x - 3 x}{20} = \frac{3000000 - 100 x + 570000 - 19 x}{100} \Rightarrow \frac{17 x}{1} = \frac{3570000 - 119 x}{5} \Rightarrow 85 x = 3570000 - 119 x \Rightarrow 204 x = 3570000 \Rightarrow x = \frac{3570000}{204} \Rightarrow x = 17500$
SO,
Cost price of first T.V. = Rs .17500
And
Cost price of second T.V. = 30000 - 17500 = Rs . 12500 ( Ans )

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