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Vector Component

A⃗ = 2 î + 3 ...

Question

$\to A = 2^i + 3^j +^k$ and $\to = 4^i + 3^j$ . Magnitude of the component of vector $\to A$ along vector $\to B$ is .

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Solution

$\to A . \to B = A B c o s θ$
$A c o s θ = \frac{\to A . \to B}{B}$
$A c o s θ = \frac{(2^i + 3^j +^k) . (4^i + 3^j)}{5} = 3.4$

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