A-3 -4 -2 k- B-6 - -3 k- Find a vector parallel to A- whose magnitude is equal to that of B-

The correct option is D √(46/29)(3 î+4 ĵ+2 k̂) Let, #160; x⃗ be the #160;vector parallel to A⃗ whose magnitude is equal to that of B⃗ ...

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Byju's Answer

Standard XII

Physics

Vector Addition

A⃗=3 î+4 ĵ+2 ...

Question

$\to A = 3^i + 4^j + 2^k$
$\to B = 6^i -^j + 3^k$ .
Find a vector parallel to $\to A$ whose magnitude is equal to that of $\to B$ .

\sqrt{\frac{46}{29}} (3^i + 4^j + 2^k)

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\sqrt{\frac{46}{29}} (6^i -^j + 3^k)

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\sqrt{\frac{29}{46}} (3^i + 4^j + 2^k)

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Solution

The correct option is D $\sqrt{\frac{46}{29}} (3^i + 4^j + 2^k)$
Let, $\to x$ be the vector parallel to $\to A$ whose magnitude is equal to that of $\to B$ .
Thus, $\to x = A | B | = \frac{(3^i + 4^j + 2^k) \sqrt{36 + 1 + 9}}{\sqrt{9 + 16 + 4}}$ $= \sqrt{\frac{46}{29}} (3^i + 4^j + 2^k)$

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→A=3^i+4^j+2^k →B=6^i−^j+3^k. Find a vector parallel to →A whose magnitude is equal to that of →B.

The correct option is D √4629(3^i+4^j+2^k)Let, →x be the vector parallel to →A whose magnitude is equal to that of →B.Thus, →x=A|B|=(3^i+4^j+2^k)√36+1+9√9+16+4=√4629(3^i+4^j+2^k)

$\to A = 3^i + 4^j + 2^k$
$\to B = 6^i -^j + 3^k$ .
Find a vector parallel to $\to A$ whose magnitude is equal to that of $\to B$ .

The correct option is D $\sqrt{\frac{46}{29}} (3^i + 4^j + 2^k)$
Let, $\to x$ be the vector parallel to $\to A$ whose magnitude is equal to that of $\to B$ .
Thus, $\to x = A | B | = \frac{(3^i + 4^j + 2^k) \sqrt{36 + 1 + 9}}{\sqrt{9 + 16 + 4}}$ $= \sqrt{\frac{46}{29}} (3^i + 4^j + 2^k)$