A- and B- are two vectors and - is the angle between them- if - A-B- - - - 3 A-B- the value of - is

The correct option is D 60 ^ ∘ 1193321Here, |A||B|sinθ=√(3)|A||B|cosθ tanθ=√(3) θ=60^0 Option B is the correct answer ...

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Standard XII

Physics

Multiplication with Vectors

A⃗ and B⃗ a...

Question

$\to A$ and $\to B$ are two vectors and $θ$ is the angle between them, if $| \to A \times \to B | = \sqrt{3} (\to A \cdot \to B)$ the value of $θ$ is

90^{\circ}

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60^{\circ}

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45^{\circ}

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30^{\circ}

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Solution

The correct option is D $60^{\circ}$
1193321

Here,

$| A | | B | sin θ = \sqrt{3} | A | | B | cos θ$

$t a n θ = \sqrt{3}$

$θ = 60^{0}$

Option $B$ is the correct answer

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Similar questions

\to A

and

\to B

are two vectors and

θ

is the angle between them, if

| \to A \times \to B | = \sqrt{3} (\to A . \to B)

, the value of

θ

Q. If

\to a

and

\to b

are unequal vectors such that

(\to a - \to b) \times [(\to b + \to a) \times (2 \to a + \to b)] = \to a + \to b

, then the angle

θ

between

\to a

and

\to b

Q. Let

\to a, \to b

and

\to c

be three non-zero vectors such that no two of them are collinear and

(\to a \times \to b) \times \to c = \frac{1}{3} | \to b | | \to c | \to a

. If

θ

is the angle between vectors

\to b

and

\to c

, then a value of sin

θ

is :

Q. If

θ

is the angle between two vectors

\to a

and

\to b

,then

\to a \cdot \to b \geq 0

only when

\to A

and

\to B

are 2 non-zero vectors if

| \to A | \times | \to B |

\to A \cdot \to B

. What is the angle between the two vectors?

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→A and →B are two vectors and θ is the angle between them, if |→A×→B|=√3(→A⋅→B) the value of θ is

The correct option is D 60∘1193321Here,|A||B|sinθ=√3|A||B|cosθtanθ=√3θ=600Option B is the correct answer

$\to A$ and $\to B$ are two vectors and $θ$ is the angle between them, if $| \to A \times \to B | = \sqrt{3} (\to A \cdot \to B)$ the value of $θ$ is

The correct option is D $60^{\circ}$
1193321

Here,

$| A | | B | sin θ = \sqrt{3} | A | | B | cos θ$

$t a n θ = \sqrt{3}$

$θ = 60^{0}$

Option $B$ is the correct answer