A- and B- are two vectors given by A- -2- -3- and B- - - The magnitude of the component of A- along B- is

The correct option is A 5 √( 2 ) Magnitude of component of A⃗ along B⃗ nbsp;=A⃗·B⃗ nbsp;| B⃗ nbsp;| nbsp; nbsp; nbsp; nbsp; ...

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Byju's Answer

Standard XII

Physics

Vector Component

A⃗ and B⃗ a...

Question

$\to A$ and $\to B$ are two vectors given by $\to A = 2^i + 3^j$ and $\to B =^i +^j$ . The magnitude of the component of $\to A$ along $\to B$ is

\frac{5}{\sqrt{2}}

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\frac{3}{\sqrt{2}}

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\frac{7}{\sqrt{2}}

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\frac{1}{\sqrt{2}}

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Solution

The correct option is A $\frac{5}{\sqrt{2}}$
Magnitude of component of $\to A$ along $\to B = \frac{\to A \cdot \to B}{∣ ∣ \to B ∣ ∣}$
$= \frac{(2^i + 3^j) \cdot (^i +^j)}{\sqrt{2}}$
$= \frac{2 + 3}{\sqrt{2}} = \frac{5}{\sqrt{2}}$

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→A and →B are two vectors given by →A=2^i+3^j and →B=^i+^j. The magnitude of the component of →A along →B is

The correct option is A 5√2Magnitude of component of →A along →B=→A⋅→B∣∣→B∣∣ =(2^i+3^j)⋅(^i+^j)√2 =2+3√2=5√2

$\to A$ and $\to B$ are two vectors given by $\to A = 2^i + 3^j$ and $\to B =^i +^j$ . The magnitude of the component of $\to A$ along $\to B$ is

The correct option is A $\frac{5}{\sqrt{2}}$
Magnitude of component of $\to A$ along $\to B = \frac{\to A \cdot \to B}{∣ ∣ \to B ∣ ∣}$
$= \frac{(2^i + 3^j) \cdot (^i +^j)}{\sqrt{2}}$
$= \frac{2 + 3}{\sqrt{2}} = \frac{5}{\sqrt{2}}$