→A is a vector which when added to the resultant of vectors (2ˆi−3ˆj+4ˆk) and (ˆi+5ˆj+2ˆk) yields a unit vector along the y-axis. Then vector →A is:
A
−3ˆi−ˆj−6ˆk
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B
3ˆi+ˆj−6ˆk
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C
3ˆi−ˆj+6ˆk
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D
3ˆi+ˆj+6ˆk
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Solution
The correct option is A−3ˆi−ˆj−6ˆk Let, B=(2ˆi−3ˆj+4ˆk) and C=(ˆi+5ˆj+2ˆk) As per the question given: A+B+C=1ˆj ∴A+(2ˆi−3ˆj+4ˆk)+(ˆi+5ˆj+2ˆk)=1ˆj ∴A=−3ˆi−ˆj−6ˆk