→A is a vector with direction cosines cosα, cosβ and cosγ. Assuming the y−z plane as a mirror, the direction cosines of the reflected image of →A in the y−z plane are
A
cosα,cosβ,cosγ
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B
cosα,−cosβ,cosγ
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C
−cosα,cosβ,cosγ
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D
−cosα,−cosβ,−cosγ
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Solution
The correct option is C−cosα,cosβ,cosγ
The directional cosines of A are cosα,cosβ,cosγ
Given that y−z plane is mirror
Only x coordinate of A will change and y,z coordinates will remain same because the point is reflected about y−z plane
On y−z plane x=0 , so the directional cosine of reflected point in x direction is −cosα
Therefore the directional cosines of reflected image is −cosα,cosβ,cosγ