The correct option is C (#160;a.#160;q)#160;p (#160;a.#160;p)k+(#160;b.#160;a)(#160;a×#160;c) =a⃗× ((b⃗.a⃗)c⃗ (b⃗.c⃗) a⃗+p⃗×q⃗) =(b⃗.a⃗) a⃗×c⃗ + ...

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Bicyclo Compounds

a⃗×b⃗×c⃗×a⃗+p...

Question

$\to a \times {\to b \times (\to c \times \to a) + (\to p \times \to q)} =$

(\to a . \to q) \to p - (\to a . \to p) k + (\to b . \to a) (\to a \times \to c) - (\to b \times \to c)

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(\to a . \to q) \to p - (\to a . \to p) k + (\to b . \to a) (\to a \times \to c)

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\to a \times (\to p \times \to q) + [\to a \to b \to c] \to c

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\to a \times (\to p \times \to a)

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Solution

The correct option is C $(\to a . \to q) \to p - (\to a . \to p) k + (\to b . \to a) (\to a \times \to c)$
$= \to a \times ((\to b . \to a) \to c - (\to b . \to c) \to a + \to p \times \to q)$
$= (\to b . \to a) \to a \times \to c + \to a \times (\to p \times \to q)$
$(\to b . \to a) \to a \times \to c - (\to a . \to p) \to q + (\to a . \to q) \to P$

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Similar questions

\to a, \to b, \to c

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¯ ¯ ¯ a, ¯ ¯ b, ¯ ¯ c

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