The correct option is A (a⃗.d⃗)[a⃗ b⃗ c⃗] [a× b a × c d]=(a× b).[(a × c) × d]=(a× b).[(a.d)c (c.d)a] =(a.d).[(a× b) × c] (c.d)[(a × b × a] ...

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Definition of Relations

[a⃗×b⃗a⃗×c⃗d⃗...

Question

$[\to a \times \to b \to a \times \to c \to d] =$

(\to a . \to b) [\to a \to c \to d]

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(\to a . \to d) [\to a \to b \to c]

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(\to b . \to c) [\to a \to b \to d]

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(\to a . \to c) [\to b \to c \to d]

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Solution

The correct option is A $(\to a . \to d) [\to a \to b \to c]$
$[a \times b a \times c d] = (a \times b) . [(a \times c) \times d] = (a \times b) . [(a . d) c - (c . d) a]$
$= (a . d) . [(a \times b) \times c] - (c . d) [(a \times b \times a] = (a . d) [a b c]$

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Similar questions

[\to b \to c \to d] \to a - [\to a \to c \to d] \to b + [\to a \to d \to b] \to c - [\to a \to b \to c] \to a =

[\to a \to b \to c] = 2

\frac{\to a . (\to b \times \to c)}{(\to c \times \to a) . \to b} + \frac{\to b . (\to c \times \to a)}{(\to a \times \to b) . \to c} + \frac{\to c . (\to a \times \to b)}{(\to b \times \to c) . \to a} =

[\begin{matrix} \to a & \to b & \to c \end{matrix}] = 1

\frac{\to a . \to b \times \to c}{\to c \times \to a . \to b} + \frac{\to b . \to c \times \to a}{\to a \times \to b . \to c} + \frac{\to c . \to a \times \to b}{\to b \times \to c . \to a}

\to a . \to b = \to a . \to c

\to a \times \to b = \to a \times \to c

[\to a \to b \to c + \to d] = [\to a \to b \to c] + [\to a \to b \to d]

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