A-b-a-b-b-c-b-c-c-a-c-a-

The correct option is B 2(a⃗×b⃗+b⃗×c⃗+c⃗×a⃗) Solving #160; = a⃗×b⃗+b⃗×a⃗ b⃗×c⃗+c⃗×b⃗ c⃗×a⃗+a⃗×c⃗ = 2b⃗×a⃗+2c⃗×b⃗+2a⃗×c⃗ = 2(b⃗×a⃗+c⃗×b⃗+ ...

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Subtraction of Decimals

a⃗+b⃗×a⃗-b⃗+b...

Question

$(\to a + \to b) \times (\to a - \to b) + (\to b + \to c) \times (\to b - \to c) + (\to c + \to a) \times (\to c - \to a) =$

2 (\to a \times \to b + \to b \times \to c + \to c \times \to a)

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- 2 (\to a \times \to b + \to b \times \to c + \to c \times \to a)

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(\to a \times \to b + \to b \times \to c + \to c \times \to a)

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- (\to a \times \to b + \to b \times \to c + \to c \times \to a)

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Solution

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Similar questions

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

[\to a + 2 \to b - \to c, \to a - \to b, \to a - \to b - \to c] =

[\to a, \to b, \to c] \neq [\to b, \to c, \to a] \neq [\to c, \to a, \to b]

\to a =^i +^j +^k

\to b = - 3^i +^k

\to c =^i + 2^j + 3^k

A)

[\to a \times \to b

\to b \times \to c

\to c \times \to a]

B)

[\to a + \to b

\to b + \to c

\to c + \to a]

C)

[\to a

\to b

\to c]

[\to a

\to b

\to c]^{- 1}

D)

[\to a - \to b

\to b - \to c

\to c - \to a]

[\to a - \to b

\to b - \to c

\to c - \to a] + [\to a \times \to b

\to b \times \to c

\to c \times \to a]

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