→a,→b,→c are three non-coplanar vectors such that →r1=→a−→b+→c,→r2=→b+→c−→a , →r3=→c+→a−→b,→r=2→a−2→b+4→c if →r=x1→r1+x2→r2+x3→r3 then
A
x1+x2+x3=4
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B
x1=72
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C
x1+x3=3
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D
All the above
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Solution
The correct option is A All the above →r=x1→r1+x2→r2+x3→r3 2→a−2→b+4→c=(x1−x2+x3)→a+(−x1+x2−x3)→b+(x1+x2+x3)→c x1−x2−x3=2-----------(1) −x1+x2−x3=−2---------(2) x1+x2+x3=4 ----------(3) x2=1x1+x3=3