I- a-i- -j- a-j- -k- a-k- is equal to

The correct option is A 2a⃗ Let a⃗=î+ĵ+k̂ î×(a⃗×î)+ĵ×(a⃗×ĵ)+k̂×(a⃗×k̂) =(î·î)a⃗ (î·a⃗)î+(ĵ·ĵ)a⃗ (ĵ·a⃗)ĵ+(k̂·k̂)a⃗ (k̂·a⃗)k̂ =1×a⃗ (î·a ...

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Applications of Cross Product

i⃗× a⃗×i⃗ +j⃗...

Question

$\to i \times (\to a \times \to i) + \to j \times (\to a \times \to j) + \to k \times (\to a \times \to k)$ is equal to

2 \to a

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3 \to a

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\to 0

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None of these

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Solution

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Similar questions

\to i \times (\to a \times \to i) + \to j \times (\to a \times \to j) + \to k \times (\to a \times \to k)

\to i, \to j, \to k

\to a = \to i + \to j + \to k, \to a = 2 \to i + \to k, \to c = 2 \to i + \to j + \to k; \to d = \to i + \to j + 2 \to k

(\to a \times \to b) \times (\to c \times \to d) = [\to a \to b \to d] \to c - [\to a \to b \to c] \to d

\to a

\to i

\to k

\to b

\to i

\to j

\to k

\to c

\to i

\to j

\to k

\to a

\to b

\to c

\to a . \to b = 1

\to a \times \to b = \to j - \to k

\to a = \to i + \to j + \to k

\to b

\to a = a_{1}^i + a_{2}^j + a_{3}^k

| \to a \times \to i |^{2} + | \to a \times \to j |^{2} + | \to a \times \to k |^{2} = | 2 \to a |^{2}

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